負の二項定理と重複組合せ
(1-x)^{-d} = \sum_{n=0}^\infty H_{d-1}^{n+1} x^n
(1-x)^{-d} = \sum_{n=0}^\infty \binom{n+d-1}{d-1}x^n
H^n_k = \binom{n + k - 1}{k} = \frac{(n + k - 1)!}{k!(n - 1)!}
Related Pages
"Engineer's way of creating knowledge" the English version of my book is now available on [Engineer's way of creating knowledge]
(C)NISHIO Hirokazu / Converted from [Scrapbox] at [Edit]